Powershell - Get path location via Find-Path Function

Question

So i wrote the code below

$datum_vandaag = $(Get-Date).toString('yyyy-MM-dd')
$maand = $datum_vandaag.substring(5, 2)

if (-Not (Test-Path -Path "C:\Users\Nick\Desktop\ITIL\**" -Include *$maand*)) { #(contains words gelijk aan (get-date)
    md -Path "C:\Users\Nick\Desktop\ITIL\[??????]\$datum_vandaag"                        # Makes folder with name of current date in path:
    }
 
Else{Write-Output "test output"
}

The IF function is looking if in the path Desktop\ITIL** there is a folder that has the same number as the current date (07 is july) somewhere in the name of the folder.

Now i would like to make a new folder in the folder that is found by the command below :

Test-Path -Path "C:\Users\Nick\Desktop\ITIL\**" -Include *$maand*

How could i get acces to this path so i can use it in the md command (now marked with [??????] in the code) Because currently i only receive if a folder is found, false or true. All i could find what possibly would work is get-path or resolve-path but I don't know how to implement this.

David Martin David Martin · Accepted Answer · 2020-07-17T12:56:58

It's difficult to fully understand what you are asking, but I think the command you are looking for is Get-Item which will return an object to the named folder.

Something like this might work:

$path = Get-Item -Path "C:\Users\Nick\Desktop\ITIL\**" -Include *$maand*
if ($path) {
  $newPath = Join-Path -Path $path -ChildPath $datum_vandaag
  New-Item -Path $newPath -ItemType Directory
}

Powershell - Get path location via Find-Path Function

1 Answers