How to get django model field into html template?

Question

First time posting on here and new to Django, sorry in advance.

Im trying to plug the name field from my model into my html template, which I will then convert to a pdf.

Everything involving the html to pdf conversion is working, I just cant seem to get the name field from my model to work into the html_template when it renders.

Ive tried adding 'name' : name into the context_dict within the render_to_pdf view, and that did not work.

I think I am likely missing something in my view.

pdf_template.html

{% block content %}
   <div class="container">
       <div class="row">

               <p> **{{name}}** </p>
               
   </div>
{% endblock %}

models.py

class User(models.Model):

    username = models.CharField(max_length = 20, primary_key=True)
    name = models.CharField(max_length = 20)
    
    def __str__(self): 
        return self.name

views.py

def render_to_pdf(template_src, context_dict={}):
    template = get_template(template_src)
    html  = template.render(context_dict)
    result = BytesIO()
    pdf = pisa.pisaDocument(BytesIO(html.encode("ISO-8859-1")), result)
    if not pdf.err:
        return HttpResponse(result.getvalue(), content_type='application/pdf')
    return None

Answer 1

It's unclear what you're trying to do/ask.

If you want to list out all the user names, you can do this :

def listView(req):
    users = User.objects.all
    return render(request, 'home.html', {'names': users})

And then in your template :

<div class="container">
{% for name in names%}
        <p>{{ name.username }}</P       
</div>

Answer 2

This is how you'd need to structure your function and call it with your current design. If name was none or an empty string, it wouldn't appear.

def render_to_pdf(template_src, context_dict=None):
    if context_dict is None:
        context_dict = {}
    template = get_template(template_src)
    html  = template.render(context_dict)
    ...


render_to_pdf('template/path/...', {'name': "some name"})