STM32L4R5xx hangs when an external interrupt is enabled

Question

I would like to use the pin PC3 as an external interrupt. Whenever I enable the interrupt I end up in the infinite loop.

This is how I init a gpio and its interrupt:

__HAL_RCC_GPIOC_CLK_ENABLE();
 GPIO_InitStruct.Pin = GPIO_PIN_3;
 GPIO_InitStruct.Mode = GPIO_MODE_IT_FALLING;
 GPIO_InitStruct.Pull = GPIO_NOPULL;
 HAL_GPIO_Init(GPIOC, &GPIO_InitStruct);
 /* EXTI interrupt init*/
 HAL_NVIC_SetPriority(EXTI3_IRQn, 0, 0);
 HAL_NVIC_EnableIRQ(EXTI3_IRQn);

I have checked hardware and all signals are like they should be. I tried PB0 and PC3 and the result is the same.

Anyone who knows how to play with stm32l4 and exti?

The infinite loop:

Default_Handler:
Infinite_Loop:
    b   Infinite_Loop
    .size   Default_Handler, .-Default_Handler

I dont even reach an interrupt here (I have a break point there)

void EXIT3_IRQnHandler(void)
{
    HAL_GPIO_EXTI_IRQHandler(GPIO_PIN_3);
    if(!HAL_GPIO_ReadPin(GPIOC, GPIO_PIN_3))
    {
               HAL_GPIO_TogglePin(GPIOB, GPIO_PIN_7);
               HAL_GPIO_TogglePin(GPIOG, GPIO_PIN_14);
    }
    EXTI_ClearITPendingBit(EXTI3_IRQn);
}

Maybe that is important to mention that I also have SPI configuration in the same project (SPI1).

Which infinite while loop do you end up in? In the hardfault interrupt? And Can you show us your IRQ function of the interrupt? — Hein Wessels

user2071943 user2071943 · Accepted Answer · 2018-08-19T20:53:46

If ISR name is not correct it will use some default error code (its name depends on configuration), as happens in your case.

In my code its named EXTI3_IRQHandler not EXTI3_IRQnHandler.

Check in your startup file (in my setup it is called startup_stm32l432xx.s) for ISR names to be used.

STM32L4R5xx hangs when an external interrupt is enabled

1 Answers