Extracting MSDeploy Zip package using variables

3
votes

I’m setting up an automated build in VSTS that will FTP the published files to my server.

I have this working but the way I’ve achieved it, I feel is hacky and non-sustainable.

the process as you can see from the screenshots will publish the artefact which consists of a readme, cmd file and a zip containing all my publish files and then I extract the ZIP with the very explicit location below.

$(Build.ArtifactStagingDirectory)\temp\Content\d_C\a\1\s\IntermittentBug\IntermittentBug\obj\Release_EukHosts\Package\PackageTmp

I’m using a hosted build server in VSTS but as the path contains

d_C\a\1\s\

I assume this will change in time. What I need is a variable to cater for this path so it will always succeed.

How can I update this to make it more efficient and sustainable?

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2
msbuildazure-devopsazure-pipelines
Do you solve this issue? - starian chen-MSFT

2 Answers

3
votes

First, as jessebouwing said that the variable is called Build.SourcesDirectory.

Regarding the path structure, the simple way is specifying /p:PackageTempRootDir="" msbuild argument in Visual Studio Build task to remove the source path structure, then the path will be like Content\D_C\PackageTmp.

On the other hand, you also can publish the web app through File System mode.

2
votes

This variable is caught in a predefined variable called Build.SourcesDirectory. see the complete list of predefined variables here.

In your batch or powershell scripts this variable is available as a environment variable called %BUILD_SOURCESDIRECTORY% / $env:BUILD_SOURCESDIRECTORY.