I need to post data to a REST interface, however the receiving host is using a self-signed certificate (and this is not about to change) so I need to ignore the obvious certificate validation error that I receive.
My initial script looked like this:
from urllib.request import Request, urlopen
from urllib.parse import urlencode
post_url = "https://myserver.mydomain.com:30005/myapipath"
post_payload = { "event": { "Title": "Something, sometime, something, Python"} }
post_headers = {'Content-Type': 'application/xml'}
omi_post = Request(url=post_url, data=post_payload, headers=post_headers)
urlopen(omi_post)
And as mentioned, this generates the following stacktrace:
Traceback (most recent call last): File "C:\Users\myusername\AppData\Local\Programs\Python\Python36\lib\urllib\request.py", line 1318, in do_open encode_chunked=req.has_header('Transfer-encoding')) File "C:\Users\myusername\AppData\Local\Programs\Python\Python36\lib\http\client.py", line 1239, in request self._send_request(method, url, body, headers, encode_chunked) File "C:\Users\myusername\AppData\Local\Programs\Python\Python36\lib\http\client.py", line 1285, in _send_request self.endheaders(body, encode_chunked=encode_chunked) File "C:\Users\myusername\AppData\Local\Programs\Python\Python36\lib\http\client.py", line 1234, in endheaders self._send_output(message_body, encode_chunked=encode_chunked) File "C:\Users\myusername\AppData\Local\Programs\Python\Python36\lib\http\client.py", line 1026, in _send_output self.send(msg) File "C:\Users\myusername\AppData\Local\Programs\Python\Python36\lib\http\client.py", line 964, in send self.connect() File "C:\Users\myusername\AppData\Local\Programs\Python\Python36\lib\http\client.py", line 1400, in connect server_hostname=server_hostname) File "C:\Users\myusername\AppData\Local\Programs\Python\Python36\lib\ssl.py", line 407, in wrap_socket _context=self, _session=session) File "C:\Users\myusername\AppData\Local\Programs\Python\Python36\lib\ssl.py", line 814, in init self.do_handshake() File "C:\Users\myusername\AppData\Local\Programs\Python\Python36\lib\ssl.py", line 1068, in do_handshake self._sslobj.do_handshake() File "C:\Users\myusername\AppData\Local\Programs\Python\Python36\lib\ssl.py", line 689, in do_handshake self._sslobj.do_handshake() ssl.SSLError: [SSL: CERTIFICATE_VERIFY_FAILED] certificate verify failed (_ssl.c:777)
During handling of the above exception, another exception occurred:
Traceback (most recent call last): File "send_data.py", line 16, in urlopen(post_it_already) File "C:\Users\myusername\AppData\Local\Programs\Python\Python36\lib\urllib\request.py", line 223, in urlopen return opener.open(url, data, timeout) File "C:\Users\myusername\AppData\Local\Programs\Python\Python36\lib\urllib\request.py", line 526, in open response = self._open(req, data) File "C:\Users\myusername\AppData\Local\Programs\Python\Python36\lib\urllib\request.py", line 544, in _open '_open', req) File "C:\Users\myusername\AppData\Local\Programs\Python\Python36\lib\urllib\request.py", line 504, in _call_chain result = func(*args) File "C:\Users\myusername\AppData\Local\Programs\Python\Python36\lib\urllib\request.py", line 1361, in https_open context=self._context, check_hostname=self._check_hostname) File "C:\Users\myusername\AppData\Local\Programs\Python\Python36\lib\urllib\request.py", line 1320, in do_open raise URLError(err) urllib.error.URLError:
So I found another post that talked about adding in an SSL context, which I did as follows:
from urllib.request import Request, urlopen
from urllib.parse import urlencode
import ssl
ctx = ssl.create_default_context()
ctx.check_hostname = False
ctx.verify_mode = ssl.CERT_NONE
post_url = "https://myserver.mydomain.com:30005/myapipath"
post_payload = { "event": { "Title": "Something, sometime, something, Python"} }
post_headers = {'Content-Type': 'application/xml'}
post_it_already = Request(url=post_url, data=post_payload, headers=post_headers)
urlopen(post_it_already, context=ctx)
However this generates the following stacktrace (no matter how much I shake my fist at it):
Traceback (most recent call last): File "send_data.py", line 15, in urlopen(post_it_already, context=ctx) File "C:\Users\myusername\AppData\Local\Programs\Python\Python36\lib\urllib\request.py", line 223, in urlopen return opener.open(url, data, timeout) File "C:\Users\myusername\AppData\Local\Programs\Python\Python36\lib\urllib\request.py", line 526, in open response = self._open(req, data) File "C:\Users\myusername\AppData\Local\Programs\Python\Python36\lib\urllib\request.py", line 544, in _open '_open', req) File "C:\Users\myusername\AppData\Local\Programs\Python\Python36\lib\urllib\request.py", line 504, in _call_chain result = func(*args) File "C:\Users\myusername\AppData\Local\Programs\Python\Python36\lib\urllib\request.py", line 1361, in https_open context=self._context, check_hostname=self._check_hostname) File "C:\Users\myusername\AppData\Local\Programs\Python\Python36\lib\urllib\request.py", line 1318, in do_open encode_chunked=req.has_header('Transfer-encoding')) File "C:\Users\myusername\AppData\Local\Programs\Python\Python36\lib\http\client.py", line 1239, in request self._send_request(method, url, body, headers, encode_chunked) File "C:\Users\myusername\AppData\Local\Programs\Python\Python36\lib\http\client.py", line 1285, in _send_request self.endheaders(body, encode_chunked=encode_chunked) File "C:\Users\myusername\AppData\Local\Programs\Python\Python36\lib\http\client.py", line 1234, in endheaders self._send_output(message_body, encode_chunked=encode_chunked) File "C:\Users\myusername\AppData\Local\Programs\Python\Python36\lib\http\client.py", line 1064, in _send_output + b'\r\n' TypeError: can't concat str to bytes
I'm at a loss as to why it's complaining about concatenating a string with a bytes object. I assume it doesn't like my string type URL and my data type payload and headers? However I'm unsure what to do next.
Or is this a classic case of someone taking 2 separate sample codes and expecting them to work together when they are in fact like peanuts and bubble gum?