I am new to Swift and trying to learn how to implement NSTreeController with NSOutlineView. I've been following several guides which shows such examples, but I keep getting an error. I followed step by step and/or try to run their source codes if available, but I was getting same error. I come to think there is some change in Swift 4 which makes these Swift 3 examples to produce error. As there are not many examples done in Swift 4, I decided I'd give a try by asking the question here.
The error I'm getting is:
this class is not key value coding-compliant for the key isLeaf.
I believe that error is coming from the key path set up for NSTreeController:
However I am not sure what needs to be done to fix the error.
I have simple model class called Year.
class Year: NSObject {
var name: String
init(name: String) {
self.name = name
}
func isLeaf() -> Bool {
return true
}
}
My view controller looks like this.
class ViewController: NSViewController, NSOutlineViewDataSource, NSOutlineViewDelegate {
@IBOutlet weak var outlineView: NSOutlineView!
@IBOutlet var treeController: NSTreeController!
override func viewDidLoad() {
super.viewDidLoad()
addData()
outlineView.delegate = self
outlineView.dataSource = self
}
func addData() {
let root = ["name": "Year", "isLeaf": false] as [String : Any]
let dict: NSMutableDictionary = NSMutableDictionary(dictionary: root)
dict.setObject([Year(name: "1999"), Year(name: "2000")], forKey: "children" as NSCopying)
treeController.addObject(dict)
}
func isHeader(item: Any) -> Bool {
if let item = item as? NSTreeNode {
return !(item.representedObject is Year)
} else {
return !(item is Year)
}
}
func outlineView(_ outlineView: NSOutlineView, viewFor tableColumn: NSTableColumn?, item: Any) -> NSView? {
if isHeader(item: item) {
return outlineView.makeView(withIdentifier: NSUserInterfaceItemIdentifier(rawValue: "HeaderCell"), owner: self)!
} else {
return outlineView.makeView(withIdentifier: NSUserInterfaceItemIdentifier(rawValue: "DataCell"), owner: self)!
}
}
}
When I run the program, it causes no issue, but when I expand the node to show the two children of the root, it is giving the error I mentioned above.