Keras: how to get tensor dimensions inside custom loss?

Question

I'm trying to write my custom loss function: I want to apply categorical_crossentropy to the parts of input vector and then sum.

Assume y_true, y_pred are 1D vectors.

Code:

def custom_loss(y_true, y_pred):

    loss_sum= 0.0
    for i in range(0,y_true.shape[0],dictionary_dims):
        loss_sum+= keras.backend.categorical_crossentropy(y_true[i*dictionary_dims:(i+1)*dictionary_dims], y_pred[i*dictionary_dims:(i+1)*dictionary_dims])

    return loss_sum

But I get an error:

    for i in range(0,y_true.shape[0],dictionary_dims):
TypeError: __index__ returned non-int (type NoneType)

So how to access shape of input tensors to get subset of tensor?

Update: Also tried to write loss via tensorflow directly:

def custom_loss_tf(y_true, y_pred):

    print('tf.shape(y_true)',tf.shape(y_true)) #
    print('type(tf.shape(y_true))',type(tf.shape(y_true))) #

    sys.exit()

    loss_sum= 0.0
    for i in range(0,y_true.shape[0],dictionary_dims):
        loss_sum+= keras.backend.categorical_crossentropy(y_true[i*dictionary_dims:(i+1)*dictionary_dims], y_pred[i*dictionary_dims:(i+1)*dictionary_dims])

    return loss_sum

Output:

tf.shape(y_true) Tensor("Shape:0", shape=(2,), dtype=int32)
type(tf.shape(y_true)) <class 'tensorflow.python.framework.ops.Tensor'>

Not sure what is shape=(2,) mean, but this is not what I'm expecting, because model.summary() shows that last layer is (None, 26):

_________________________________________________________________
Layer (type)                 Output Shape              Param #
=================================================================
input_1 (InputLayer)         (None, 80, 120, 3)        0
_________________________________________________________________
conv2d_1 (Conv2D)            (None, 80, 120, 32)       896
_________________________________________________________________
max_pooling2d_1 (MaxPooling2 (None, 40, 60, 32)        0
_________________________________________________________________
activation_1 (Activation)    (None, 40, 60, 32)        0
_________________________________________________________________
conv2d_2 (Conv2D)            (None, 40, 60, 32)        9248
_________________________________________________________________
max_pooling2d_2 (MaxPooling2 (None, 20, 30, 32)        0
_________________________________________________________________
activation_2 (Activation)    (None, 20, 30, 32)        0
_________________________________________________________________
conv2d_3 (Conv2D)            (None, 20, 30, 64)        18496
_________________________________________________________________
max_pooling2d_3 (MaxPooling2 (None, 10, 15, 64)        0
_________________________________________________________________
activation_3 (Activation)    (None, 10, 15, 64)        0
_________________________________________________________________
conv2d_4 (Conv2D)            (None, 10, 15, 64)        36928
_________________________________________________________________
max_pooling2d_4 (MaxPooling2 (None, 5, 7, 64)          0
_________________________________________________________________
activation_4 (Activation)    (None, 5, 7, 64)          0
_________________________________________________________________
flatten_1 (Flatten)          (None, 2240)              0
_________________________________________________________________
head (Dense)                 (None, 26)                58266
=================================================================

Marcin Możejko Marcin Możejko · Accepted Answer · 2017-08-03T11:38:58

Two things here:

If you want to get a tensor shape you should use int_shape function from keras.backend.
The first dimension is set to be a batch dimension so int_shape(y_true)[0] will return you a batch size. You should use int_shape(y_true)[1].

Keras: how to get tensor dimensions inside custom loss?

1 Answers