python - Django: Display Choice Value

286
votes

models.py:

class Person(models.Model):
    name = models.CharField(max_length=200)
    CATEGORY_CHOICES = (
        ('M', 'Male'),
        ('F', 'Female'),
    )
    gender = models.CharField(max_length=200, choices=CATEGORY_CHOICES)
    to_be_listed = models.BooleanField(default=True)
    description = models.CharField(max_length=20000, blank=True)

views.py:

def index(request):
    latest_person_list2 = Person.objects.filter(to_be_listed=True)
    return object_list(request, template_name='polls/schol.html',
                       queryset=latest_person_list, paginate_by=5)

On the template, when I call person.gender, I get 'M' or 'F' instead of 'Male' or 'Female'.

How to display the value ('Male' or 'Female') instead of the code ('M'/'F')?

3
pythondjangodjango-modelsdjango-templates
possible duplicate of Django print choices value – Ignacio Vazquez-Abrams
I tried this method, In my template I am using: {% for person in object_list %} some html {{person.get_gender_display() }} html {% endfor %} I am getting the following error: Exception Value: Could not parse the remainder: '()' from 'person.get_gender_display()' – Shankze
My Bad, I should not have included '()' after person.get_gender_display. Its working now. Thanks. – Shankze
Just a little comment, since gender will only be either M or F(1 character lenght) it has no sense setting the max length of the charfield to 200. With max_lenght=1 is enough, will make your site more efficient and you will ensure that you wont have wrong data. :) – Alejandro Garcia
Possible duplicate of Django templates: verbose version of a choice – Ciro Santilli 新疆再教育营六四事件法轮功郝海东

3 Answers

590
votes

It looks like you were on the right track - get_FOO_display() is most certainly what you want:

In templates, you don't include () in the name of a method. Do the following:

{{ person.get_gender_display }}
34
votes

For every field that has choices set, the object will have a get_FOO_display() method, where FOO is the name of the field. This method returns the “human-readable” value of the field.

In Views

person = Person.objects.filter(to_be_listed=True)
context['gender'] = person.get_gender_display()

In Template

{{ person.get_gender_display }}

Documentation of get_FOO_display()

-3
votes

Others have pointed out that a get_FOO_display method is what you need. I'm using this:

def get_type(self):
    return [i[1] for i in Item._meta.get_field('type').choices if i[0] == self.type][0]

which iterates over all of the choices that a particular item has until it finds the one that matches the items type