Currently I have such Types.php:
namespace Application\GraphQL;
use Application\GraphQL\Type\NodeType;
use Application\GraphQL\Type\QueryType;
use GraphQL\Type\Definition\NonNull;
use GraphQL\Type\Definition\Type;
use Application\GraphQL\Type\PersonType;
/**
* Class Types
*
* Acts as a registry and factory for your types.
*
* As simplistic as possible for the sake of clarity of this example.
* Your own may be more dynamic (or even code-generated).
*
* @package GraphQL\Examples\Blog
*/
class Types
{
private static $query;
private static $person;
private static $node;
public static function person()
{
return self::$person ?: (self::$person = new PersonType());
}
/**
* @return QueryType
*/
public static function query()
{
return self::$query ?: (self::$query = new QueryType());
}
/**
* @return NodeType
*/
public static function node()
{
return self::$node ?: (self::$node = new NodeType());
}
/**
* @return \GraphQL\Type\Definition\IDType
*/
public static function id()
{
return Type::id();
}
/**
* @return \GraphQL\Type\Definition\StringType
*/
public static function string()
{
return Type::string();
}
/**
* @param Type $type
* @return NonNull
*/
public static function nonNull($type)
{
return new NonNull($type);
}
}
In query() function it creates QueryType instance. I added to QueryType constructor PersonTable model class so that it could query persons from database.
QueryType.php
public function __construct(PersonTable $table)
{
$config = [
'name' => 'Query',
'fields' => [
'person' => [
'type' => Types::person(),
'description' => 'Returns person by id',
'args' => [
'id' => Types::nonNull(Types::id())
]
],
'hello' => Type::string()
],
'resolveField' => function($val, $args, $context, ResolveInfo $info) {
return $this->{$info->fieldName}($val, $args, $context, $info);
}
];
$this->table = $table;
parent::__construct($config);
}
I have set up factories in module\Application\src\Module.php:
/**
* @link http://github.com/zendframework/ZendSkeletonApplication for the canonical source repository
* @copyright Copyright (c) 2005-2016 Zend Technologies USA Inc. (http://www.zend.com)
* @license http://framework.zend.com/license/new-bsd New BSD License
*/
namespace Application;
use Application\Model\PersonTable;
use Application\Model\Person;
use Zend\Db\ResultSet\ResultSet;
use Zend\Db\TableGateway\TableGateway;
class Module
{
const VERSION = '3.0.2dev';
public function getConfig()
{
return include __DIR__ . '/../config/module.config.php';
}
// Add this method:
public function getServiceConfig()
{
return array(
'factories' => array(
'Application\Model\PersonTable' => function($sm) {
$tableGateway = $sm->get('PersonTableGateway');
$table = new PersonTable($tableGateway);
return $table;
},
'PersonTableGateway' => function ($sm) {
$dbAdapter = $sm->get('Zend\Db\Adapter\Adapter');
$resultSetPrototype = new ResultSet();
$resultSetPrototype->setArrayObjectPrototype(new Person());
return new TableGateway('album', $dbAdapter, null, $resultSetPrototype);
},
),
);
}
}
I am doing by this example which does not have any framework:
https://github.com/webonyx/graphql-php/tree/master/examples/01-blog
So the question is - how do I create queryType instance with injected PersonTable instance? I should somehow get from the factory the PersonTable instance but I do not understand how.
Update:
I decided to try to inject QueryType into the controller. Created such function:
public function __construct(QueryType $queryType)
{
$this->queryType = $queryType;
}
Now module\Application\src\Module.php getServiceConfig looks like this:
public function getServiceConfig()
{
return array(
'factories' => array(
'Application\Model\PersonTable' => function($sm) {
$tableGateway = $sm->get('PersonTableGateway');
$table = new PersonTable($tableGateway);
return $table;
},
'PersonTableGateway' => function ($sm) {
$dbAdapter = $sm->get('Zend\Db\Adapter\Adapter');
$resultSetPrototype = new ResultSet();
$resultSetPrototype->setArrayObjectPrototype(new Person());
return new TableGateway('album', $dbAdapter, null, $resultSetPrototype);
},
QueryType::class => function ($sm) {
return new QueryType($sm->get(PersonTable::class));
}
// when putting in namespace does not find??????????
//QueryType::class => Application\GraphQL\Type\Factories\QueryTypeFactory::class
//QueryType::class => \QueryTypeFactory::class
),
);
}
But I get error:
Catchable fatal error: Argument 1 passed to Application\Controller\IndexController::__construct() must be an instance of Application\GraphQL\Type\QueryType, none given, called in E:\projektai\php projektai\htdocs\graphQL_zend_3\vendor\zendframework\zend-servicemanager\src\Factory\InvokableFactory.php on line 32 and defined in E:\projektai\php projektai\htdocs\graphQL_zend_3\module\Application\src\Controller\IndexController.p
How can none be given if I configured in that function?
If I could inject into the controller, then I plan to do like this:
$schema = new Schema([
//'query' => Types::query()
'query' => $this->queryType
]);
So I would not need to call query() function which return the QueryType instance anyway.
And then PersonTable would be automatically injected into QueryType class.
Update:
I had created the factory, similar as in the asnswer:
class QueryTypeFactory implements FactoryInterface
{
public function __invoke(ContainerInterface $container, $requestedName, array $options = null)
{
return new QueryType($container->get(PersonTable::class));
}
}
In the IndexController I have constructor:
public function __construct(QueryType $queryType)
{
$this->queryType = $queryType;
}
In the Module.php I use this factory:
public function getServiceConfig()
{
return array(
'factories' => array(
'Application\Model\PersonTable' => function($sm) {
$tableGateway = $sm->get('PersonTableGateway');
$table = new PersonTable($tableGateway);
return $table;
},
'PersonTableGateway' => function ($sm) {
$dbAdapter = $sm->get('Zend\Db\Adapter\Adapter');
$resultSetPrototype = new ResultSet();
$resultSetPrototype->setArrayObjectPrototype(new Person());
return new TableGateway('album', $dbAdapter, null, $resultSetPrototype);
},
// QueryType::class => function ($sm) {
// //return new QueryType($sm->get(PersonTable::class));
//
// }
//QueryType::class => Application\GraphQL\Type\Factories\QueryTypeFactory::class
//QueryType::class => \QueryTypeFactory::class
QueryType::class => QueryTypeFactory::class
),
);
}
It simply does not work, I get error:
Catchable fatal error: Argument 1 passed to Application\Controller\IndexController::__construct() must be an instance of Application\GraphQL\Type\QueryType, none given, called in E:\projektai\php projektai\htdocs\graphQL_zend_3\vendor\zendframework\zend-servicemanager\src\Factory\InvokableFactory.php on line 32 and defined in E:\projektai\php projektai\htdocs\graphQL_zend_3\module\Application\src\Controller\IndexController.php on line
I also tried this way:
$queryTypeFactory = new QueryTypeFactory();
// GraphQL schema to be passed to query executor:
$schema = new Schema([
//'query' => Types::query()
//'query' => $this->queryType
// 'query' => $queryType
'query' => $queryTypeFactory()
]);
But the $queryTypeFactory() needs parameter $container. Which is not what I want, I guess. I should be able to create an instance without passing parameters.
I hope it is ok to use QueryType::class in the factories array as key. It will create with full name space which is set:
use Application\GraphQL\Type\QueryType;
And in index controller I also call that use statement.
