sass mixins with loops givies error

Question

I'm writing a sass code to get css output as given below.

 background: -webkit-linear-gradient(top, 50%);
 background: -moz-linear-gradient(top, 50%);
 background: linear-gradient(top, 50%);

The sass mixin code i wrote for this is:

@mixin linear-gradient($name, $arg1, $arg2){
    @each $vendor in ('-webkit-', '-moz-','') {
        background: #{$vendor}#{$name}(#{$arg1}, #{$arg2});
    }
}
@include linear-gradient(linear-gradient, top, 50%);

But i was getting error. Can anyone tell why?

Jeff Jenkins Jeff Jenkins · Accepted Answer · 2016-06-07T18:16:37

The $name parameter seems unnecessary so I've omitted it from my first example. The second example shows an alternative solution using $name so that it compiles the parentheses properly.

@mixin linear-gradient($arg1, $arg2){
    @each $vendor in ('-webkit-', '-moz-','') {
        background: #{$vendor}linear-gradient(#{$arg1}, #{$arg2});
    }
}

@mixin linear-gradient($name, $arg1, $arg2){
    @each $vendor in ('-webkit-', '-moz-','') {
        background: #{$vendor}$name+'('+$arg1+', '+$arg2+')';
    }
}

#myElement {
    @include linear-gradient(top, 50%);
}

/* Output */

#myElement {
  background: -webkit-linear-gradient(top, 50%);
  background: -moz-linear-gradient(top, 50%);
  background: linear-gradient(top, 50%);
}

sass mixins with loops givies error

1 Answers