Description
This regex will do the following:
- Parse the log entry and look for the date and time
- Capture the various date parts, like day, month, year, hour, minute, second, UTC offset
The Regex
\[(\d{2})/([a-zA-Z]{3})/(\d{4}):(\d{2}):(\d{2}):(\d{2})\s(-\d{4})]
Note, depending on the language you may have have to escape the / by replacing them with \/. but ever language is different.
Explanation

NODE EXPLANATION
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\[ '['
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( group and capture to \1:
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\d{2} digits (0-9) (2 times)
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) end of \1
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/ '/'
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( group and capture to \2:
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[a-zA-Z]{3} any character of: 'a' to 'z', 'A' to 'Z'
(3 times)
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) end of \2
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/ '/'
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( group and capture to \3:
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\d{4} digits (0-9) (4 times)
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) end of \3
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: ':'
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( group and capture to \4:
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\d{2} digits (0-9) (2 times)
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) end of \4
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: ':'
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( group and capture to \5:
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\d{2} digits (0-9) (2 times)
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) end of \5
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: ':'
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( group and capture to \6:
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\d{2} digits (0-9) (2 times)
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) end of \6
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\s whitespace (\n, \r, \t, \f, and " ")
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( group and capture to \7:
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- '-'
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\d{4} digits (0-9) (4 times)
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) end of \7
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] ']'
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Sample text
107.344.154.200 - - [23/Aug/2005:00:03:14 -0400] "GET /images/theimage.gif HTTP/1.0" 200 11401
Live Demo
https://regex101.com/r/hF4fP8/1
Sample Matches
[0][0] = [23/Aug/2005:00:03:14 -0400]
[0][1] = 23
[0][2] = Aug
[0][3] = 2005
[0][4] = 00
[0][5] = 03
[0][6] = 14
[0][7] = -0400