I need to perform multiplication involving 60000X70000 matrix either in python or matlab. I have a 16GB RAM and am able to load each row of the matrix easily (which is what I require). I am able to create the matrix as a whole in python but not in matlab. Is there anyway I can save the array as .mat file of v7.3 using h5py or scipy so that I can load each row separately?
1 Answers
For MATLAB v7.3 you can use hdf5storage
which requires h5py
, download the file here, extract, then type: python setup.py install
from a command prompt.
https://pypi.python.org/pypi/hdf5storage
import h5py
import hdf5storage
import numpy as np
matfiledata = {} # make a dictionary to store the MAT data in
matfiledata[u'variable1'] = np.zeros(100) # *** u prefix for variable name = unicode format, no issues thru Python 3.5; advise keeping u prefix indicator format based on feedback despite docs ***
matfiledata[u'variable2'] = np.ones(300)
hdf5storage.write(matfiledata, '.', 'example.mat', matlab_compatible=True)
If MATLAB can't load the whole thing at once, I think you'll have to save it in different variables matfiledata[u'chunk1'] matfiledata[u'chunk2'] matfiledata[u'chunk3']
etc.
Then in MATLAB if you save each chunk as a variable
load(filename,'chunk1')
do stuff...
clear chunk1
load(filename,'chunk2')
do stuff...
clear chunk2
etc.
The hdf5storage.savemat has a parameter to allow the file to be read into Python correctly in the future so worth checking out, and follows the scipy.io.loadmat format... although you can do something like this if saving data from MATLAB to make it easy to import back into Python:
MATLAB
save('example.mat','-v7.3')
Python
matdata = hdf5storage.loadmat('example.mat')
That will load back into Python as a dictionary which you can then convert into whatever datatypes you need.