179
votes

I have a data frame like this:

df
              VALUE              ABS_CALL DETECTION P-VALUE    
    1007_s_at "957.729231881542" "P"      "0.00486279317241156"
    1053_at   "320.632701283368" "P"      "0.0313356324173416" 
    117_at    "429.842323161046" "P"      "0.0170004527476119" 
    121_at    "2395.7364289242"  "P"      "0.0114473584876183" 
    1255_g_at "116.493632746934" "A"      "0.39799368200131"   
    1294_at   "739.927122116896" "A"      "0.0668649772942343" 

I want to convert the row names into the first column. Currently I use something like this to make row names as the first column:

  d <- df
  names <- rownames(d)
  rownames(d) <- NULL
  data <- cbind(names,d)

Is there a single line to do this?

8
You don't need extra packages, here's a one-liner: d <- cbind(rownames(d), data.frame(d, row.names=NULL))ssp3nc3r
The comment by @ssp3nc3r should be an accepted answerHrant

8 Answers

143
votes

You can both remove row names and convert them to a column by reference (without reallocating memory using ->) using setDT and its keep.rownames = TRUE argument from the data.table package

library(data.table)
setDT(df, keep.rownames = TRUE)[]
#    rn     VALUE  ABS_CALL DETECTION     P.VALUE
# 1:  1 1007_s_at  957.7292         P 0.004862793
# 2:  2   1053_at  320.6327         P 0.031335632
# 3:  3    117_at  429.8423         P 0.017000453
# 4:  4    121_at 2395.7364         P 0.011447358
# 5:  5 1255_g_at  116.4936         A 0.397993682
# 6:  6   1294_at  739.9271         A 0.066864977

As mentioned by @snoram, you can give the new column any name you want, e.g. setDT(df, keep.rownames = "newname") would add "newname" as the rows column.

166
votes

Or you can use dplyr's add_rownames which does the same thing as David's answer:

library(dplyr)
df <- tibble::rownames_to_column(df, "VALUE")

UPDATE (mid-2016): (incorporated to the above)

old function called add_rownames() has been deprecated and is being replaced by tibble::rownames_to_column() (same functions, but Hadley refactored dplyr a bit).

96
votes

A one line option is :

df$names <- rownames(df)
35
votes

Alternatively, you can create a new dataframe (or overwrite the current one, as the example below) so you do not need to use of any external package. However this way may not be efficient with huge dataframes.

df <- data.frame(names = row.names(df), df)
20
votes

Moved my comment into an answer per suggestion above:

You don't need extra packages, here's a one-liner:

d <- cbind(rownames(d), data.frame(d, row.names=NULL))
6
votes

dplyr::as_data_frame(df, rownames = "your_row_name") will give you even simpler result.

3
votes

Or by using DBIs sqlRownamesToColumn

library(DBI)
sqlRownamesToColumn(df)
0
votes
df = data.frame(columnNameILike = row.names(df), df)