async
methods are different than normal methods. Whatever you return from async
methods are wrapped in a Task
.
If you return no value(void) it will be wrapped in Task
, If you return int
it will be wrapped in Task<int>
and so on.
If your async method needs to return int
you'd mark the return type of the method as Task<int>
and you'll return plain int
not the Task<int>
. Compiler will convert the int
to Task<int>
for you.
private async Task<int> MethodName()
{
await SomethingAsync();
return 42;//Note we return int not Task<int> and that compiles
}
Sameway, When you return Task<object>
your method's return type should be Task<Task<object>>
public async Task<Task<object>> MethodName()
{
return Task.FromResult<object>(null);//This will compile
}
Since your method is returning Task
, it shouldn't return any value. Otherwise it won't compile.
public async Task MethodName()
{
return;//This should work but return is redundant and also method is useless.
}
Keep in mind that async method without an await
statement is not async
.
return;
works also ... ! – David Duryvoid
function. – binki