How remove items from ArrayCollection in flex?

Question

This is my ArrayCollection I want to remove "Label:"Taxes", Value:2000" line from this arrayCollection. Guys how can do that without using forloops or using forloop?

public var expenses:ArrayCollection = new ArrayCollection([
            {Label:"Taxes", Value:2000},
            {Label:"Rent", Value:1000},
            {Label:"Bills", Value:100},
            {Label:"Car", Value:450},
            {Label:"Gas", Value:100},
            {Label:"Food", Value:200}
        ]);

Answer 1

For doing that you need to know item index. So expenses.removeItemAt(0) will work for you. If you have object but don't know index you can get it with expenses.getItemIndex(myObject) and then remove it.

Answer 2

            public var expenses:ArrayCollection = new ArrayCollection([
            {Label:"Taxes", Value:2000},
            {Label:"Rent", Value:1000},
            {Label:"Bills", Value:100},
            {Label:"Car", Value:450},
            {Label:"Gas", Value:100},
            {Label:"Food", Value:200}
        ]);


            var tempArr:ArrayCollection = new ArrayCollection(); // temporary ArrayCollection

            tempArr = ObjectUtil.copy(expenses) as ArrayCollection; //copy expences ArrayCollecttion to temp arrray before delete items

            for(var i:int=0;i<expenses.length;i++)
            {
                if(expenses[i].Label.toString()==label)
                {
                    tempArr.removeItemAt(i);
                }
            } 

Answer 3

//Removing object using "remove" method as following:

trace("Remove First Item: "+ expenses.removeItemAt(0));

//Removing object using loop as following:

var indetToDelete:Object = expenses[expenses.length - expenses.length];

for(var item:int=0; item<expenses.length ; item++){
                trace("Label:"+expenses[item].Label+"Value:"+expenses[item].Value);

if((expenses[item].Label == indetToDelete.Label) && (expenses[item].Value ==  indetToDelete.Value)){

expenses.removeItemAt(item);
}

}

Hope this may help you.