grep without showing path/file:line

Question

How do you grep and only return the matching line? i.e. The path/filename is omitted from the results.

In this case I want to look in all .bar files in the current directory, searching for the term FOO

find . -name '*.bar' -exec grep -Hn FOO {} \;

Answer 1

No need to find. If you are just looking for a pattern within a specific directory, this should suffice:

grep -hn FOO /your/path/*.bar

Where -h is the parameter to hide the filename, as from man grep:

-h, --no-filename

Suppress the prefixing of file names on output. This is the default when there is only one file (or only standard input) to search.

Note that you were using

-H, --with-filename

Print the file name for each match. This is the default when there is more than one file to search.

Answer 2

Just replace -H with -h. Check man grep for more details on options

find . -name '*.bar' -exec grep -hn FOO {} \;

Answer 3

From the man page:

-h, --no-filename
    Suppress the prefixing of file names on output. This is the default when there
    is only one file (or only standard input) to search.