I think that what you're looking for is simply the cor.test()
function, which will return everything you're looking for except for the standard error of correlation. However, as you can see, the formula for that is very straightforward, and if you use cor.test
, you have all the inputs required to calculate it.
Using the data from the example (so you can compare it yourself with the results on page 14.6):
> cor.test(mydf$X, mydf$Y)
Pearson's product-moment correlation
data: mydf$X and mydf$Y
t = -5.0867, df = 10, p-value = 0.0004731
alternative hypothesis: true correlation is not equal to 0
95 percent confidence interval:
-0.9568189 -0.5371871
sample estimates:
cor
-0.8492663
If you wanted to, you could also create a function like the following to include the standard error of the correlation coefficient.
For convenience, here's the equation:
r = the correlation estimate and n - 2 = degrees of freedom, both of which are readily available in the output above. Thus, a simple function could be:
cor.test.plus <- function(x) {
list(x,
Standard.Error = unname(sqrt((1 - x$estimate^2)/x$parameter)))
}
And use it as follows:
cor.test.plus(cor.test(mydf$X, mydf$Y))
Here, "mydf" is defined as:
mydf <- structure(list(Neighborhood = c("Fair Oaks", "Strandwood", "Walnut Acres",
"Discov. Bay", "Belshaw", "Kennedy", "Cassell", "Miner", "Sedgewick",
"Sakamoto", "Toyon", "Lietz"), X = c(50L, 11L, 2L, 19L, 26L,
73L, 81L, 51L, 11L, 2L, 19L, 25L), Y = c(22.1, 35.9, 57.9, 22.2,
42.4, 5.8, 3.6, 21.4, 55.2, 33.3, 32.4, 38.4)), .Names = c("Neighborhood",
"X", "Y"), class = "data.frame", row.names = c(NA, -12L))
?cor.test
instead. – A5C1D2H2I1M1N2O1R2T1