786
votes

Right, so I have an enumerable and wish to get distinct values from it.

Using System.Linq, there's, of course, an extension method called Distinct. In the simple case, it can be used with no parameters, like:

var distinctValues = myStringList.Distinct();

Well and good, but if I have an enumerable of objects for which I need to specify equality, the only available overload is:

var distinctValues = myCustomerList.Distinct(someEqualityComparer);

The equality comparer argument must be an instance of IEqualityComparer<T>. I can do this, of course, but it's somewhat verbose and, well, cludgy.

What I would have expected is an overload that would take a lambda, say a Func<T, T, bool>:

var distinctValues = myCustomerList.Distinct((c1, c2) => c1.CustomerId == c2.CustomerId);

Anyone know if some such extension exists, or some equivalent workaround? Or am I missing something?

Alternatively, is there a way of specifying an IEqualityComparer inline (embarrass me)?

Update

I found a reply by Anders Hejlsberg to a post in an MSDN forum on this subject. He says:

The problem you're going to run into is that when two objects compare equal they must have the same GetHashCode return value (or else the hash table used internally by Distinct will not function correctly). We use IEqualityComparer because it packages compatible implementations of Equals and GetHashCode into a single interface.

I suppose that makes sense.

19
see stackoverflow.com/questions/1183403/… for a solution using GroupByuser943105
Thanks for the Anders Hejlsberg update!Tor Haugen
Nope, it doesn't make sense - how would two objects which contain identical values can return two different hash-codes??G.Y
It could help - solution for .Distinct(new KeyEqualityComparer<Customer,string>(c1 => c1.CustomerId)), and explain why GetHashCode() is important to work properly.marbel82
Related / possible duplicate of: LINQ's Distinct() on a particular propertyMarc.2377

19 Answers

1083
votes
IEnumerable<Customer> filteredList = originalList
  .GroupBy(customer => customer.CustomerId)
  .Select(group => group.First());
519
votes

It looks to me like you want DistinctBy from MoreLINQ. You can then write:

var distinctValues = myCustomerList.DistinctBy(c => c.CustomerId);

Here's a cut-down version of DistinctBy (no nullity checking and no option to specify your own key comparer):

public static IEnumerable<TSource> DistinctBy<TSource, TKey>
     (this IEnumerable<TSource> source, Func<TSource, TKey> keySelector)
{
    HashSet<TKey> knownKeys = new HashSet<TKey>();
    foreach (TSource element in source)
    {
        if (knownKeys.Add(keySelector(element)))
        {
            yield return element;
        }
    }
}
44
votes

To Wrap things up . I think most of the people which came here like me want the simplest solution possible without using any libraries and with best possible performance.

(The accepted group by method for me i think is an overkill in terms of performance. )

Here is a simple extension method using the IEqualityComparer interface which works also for null values.

Usage:

var filtered = taskList.DistinctBy(t => t.TaskExternalId).ToArray();

Extension Method Code

public static class LinqExtensions
{
    public static IEnumerable<T> DistinctBy<T, TKey>(this IEnumerable<T> items, Func<T, TKey> property)
    {
        GeneralPropertyComparer<T, TKey> comparer = new GeneralPropertyComparer<T,TKey>(property);
        return items.Distinct(comparer);
    }   
}
public class GeneralPropertyComparer<T,TKey> : IEqualityComparer<T>
{
    private Func<T, TKey> expr { get; set; }
    public GeneralPropertyComparer (Func<T, TKey> expr)
    {
        this.expr = expr;
    }
    public bool Equals(T left, T right)
    {
        var leftProp = expr.Invoke(left);
        var rightProp = expr.Invoke(right);
        if (leftProp == null && rightProp == null)
            return true;
        else if (leftProp == null ^ rightProp == null)
            return false;
        else
            return leftProp.Equals(rightProp);
    }
    public int GetHashCode(T obj)
    {
        var prop = expr.Invoke(obj);
        return (prop==null)? 0:prop.GetHashCode();
    }
}
20
votes

No there is no such extension method overload for this. I've found this frustrating myself in the past and as such I usually write a helper class to deal with this problem. The goal is to convert a Func<T,T,bool> to IEqualityComparer<T,T>.

Example

public class EqualityFactory {
  private sealed class Impl<T> : IEqualityComparer<T,T> {
    private Func<T,T,bool> m_del;
    private IEqualityComparer<T> m_comp;
    public Impl(Func<T,T,bool> del) { 
      m_del = del;
      m_comp = EqualityComparer<T>.Default;
    }
    public bool Equals(T left, T right) {
      return m_del(left, right);
    } 
    public int GetHashCode(T value) {
      return m_comp.GetHashCode(value);
    }
  }
  public static IEqualityComparer<T,T> Create<T>(Func<T,T,bool> del) {
    return new Impl<T>(del);
  }
}

This allows you to write the following

var distinctValues = myCustomerList
  .Distinct(EqualityFactory.Create((c1, c2) => c1.CustomerId == c2.CustomerId));
19
votes

Shorthand solution

myCustomerList.GroupBy(c => c.CustomerId, (key, c) => c.FirstOrDefault());
13
votes

This will do what you want but I don't know about performance:

var distinctValues =
    from cust in myCustomerList
    group cust by cust.CustomerId
    into gcust
    select gcust.First();

At least it's not verbose.

12
votes

Here's a simple extension method that does what I need...

public static class EnumerableExtensions
{
    public static IEnumerable<TKey> Distinct<T, TKey>(this IEnumerable<T> source, Func<T, TKey> selector)
    {
        return source.GroupBy(selector).Select(x => x.Key);
    }
}

It's a shame they didn't bake a distinct method like this into the framework, but hey ho.

4
votes

Something I have used which worked well for me.

/// <summary>
/// A class to wrap the IEqualityComparer interface into matching functions for simple implementation
/// </summary>
/// <typeparam name="T">The type of object to be compared</typeparam>
public class MyIEqualityComparer<T> : IEqualityComparer<T>
{
    /// <summary>
    /// Create a new comparer based on the given Equals and GetHashCode methods
    /// </summary>
    /// <param name="equals">The method to compute equals of two T instances</param>
    /// <param name="getHashCode">The method to compute a hashcode for a T instance</param>
    public MyIEqualityComparer(Func<T, T, bool> equals, Func<T, int> getHashCode)
    {
        if (equals == null)
            throw new ArgumentNullException("equals", "Equals parameter is required for all MyIEqualityComparer instances");
        EqualsMethod = equals;
        GetHashCodeMethod = getHashCode;
    }
    /// <summary>
    /// Gets the method used to compute equals
    /// </summary>
    public Func<T, T, bool> EqualsMethod { get; private set; }
    /// <summary>
    /// Gets the method used to compute a hash code
    /// </summary>
    public Func<T, int> GetHashCodeMethod { get; private set; }

    bool IEqualityComparer<T>.Equals(T x, T y)
    {
        return EqualsMethod(x, y);
    }

    int IEqualityComparer<T>.GetHashCode(T obj)
    {
        if (GetHashCodeMethod == null)
            return obj.GetHashCode();
        return GetHashCodeMethod(obj);
    }
}
4
votes

All solutions I've seen here rely on selecting an already comparable field. If one needs to compare in a different way, though, this solution here seems to work generally, for something like:

somedoubles.Distinct(new LambdaComparer<double>((x, y) => Math.Abs(x - y) < double.Epsilon)).Count()
3
votes

Take another way:

var distinctValues = myCustomerList.
Select(x => x._myCaustomerProperty).Distinct();

The sequence return distinct elements compare them by property '_myCaustomerProperty' .

3
votes

You can use LambdaEqualityComparer:

var distinctValues
    = myCustomerList.Distinct(new LambdaEqualityComparer<OurType>((c1, c2) => c1.CustomerId == c2.CustomerId));


public class LambdaEqualityComparer<T> : IEqualityComparer<T>
    {
        public LambdaEqualityComparer(Func<T, T, bool> equalsFunction)
        {
            _equalsFunction = equalsFunction;
        }

        public bool Equals(T x, T y)
        {
            return _equalsFunction(x, y);
        }

        public int GetHashCode(T obj)
        {
            return obj.GetHashCode();
        }

        private readonly Func<T, T, bool> _equalsFunction;
    }
2
votes

You can use InlineComparer

public class InlineComparer<T> : IEqualityComparer<T>
{
    //private readonly Func<T, T, bool> equalsMethod;
    //private readonly Func<T, int> getHashCodeMethod;
    public Func<T, T, bool> EqualsMethod { get; private set; }
    public Func<T, int> GetHashCodeMethod { get; private set; }

    public InlineComparer(Func<T, T, bool> equals, Func<T, int> hashCode)
    {
        if (equals == null) throw new ArgumentNullException("equals", "Equals parameter is required for all InlineComparer instances");
        EqualsMethod = equals;
        GetHashCodeMethod = hashCode;
    }

    public bool Equals(T x, T y)
    {
        return EqualsMethod(x, y);
    }

    public int GetHashCode(T obj)
    {
        if (GetHashCodeMethod == null) return obj.GetHashCode();
        return GetHashCodeMethod(obj);
    }
}

Usage sample:

  var comparer = new InlineComparer<DetalleLog>((i1, i2) => i1.PeticionEV == i2.PeticionEV && i1.Etiqueta == i2.Etiqueta, i => i.PeticionEV.GetHashCode() + i.Etiqueta.GetHashCode());
  var peticionesEV = listaLogs.Distinct(comparer).ToList();
  Assert.IsNotNull(peticionesEV);
  Assert.AreNotEqual(0, peticionesEV.Count);

Source: https://stackoverflow.com/a/5969691/206730
Using IEqualityComparer for Union
Can I specify my explicit type comparator inline?

1
votes

A tricky way to do this is use Aggregate() extension, using a dictionary as accumulator with the key-property values as keys:

var customers = new List<Customer>();

var distincts = customers.Aggregate(new Dictionary<int, Customer>(), 
                                    (d, e) => { d[e.CustomerId] = e; return d; },
                                    d => d.Values);

And a GroupBy-style solution is using ToLookup():

var distincts = customers.ToLookup(c => c.CustomerId).Select(g => g.First());
0
votes

I'm assuming you have an IEnumerable, and in your example delegate, you would like c1 and c2 to be referring to two elements in this list?

I believe you could achieve this with a self join var distinctResults = from c1 in myList join c2 in myList on

0
votes

If Distinct() doesn't produce unique results, try this one:

var filteredWC = tblWorkCenter.GroupBy(cc => cc.WCID_I).Select(grp => grp.First()).Select(cc => new Model.WorkCenter { WCID = cc.WCID_I }).OrderBy(cc => cc.WCID); 

ObservableCollection<Model.WorkCenter> WorkCenter = new ObservableCollection<Model.WorkCenter>(filteredWC);
0
votes

The Microsoft System.Interactive package has a version of Distinct that takes a key selector lambda. This is effectively the same as Jon Skeet's solution, but it may be helpful for people to know, and to check out the rest of the library.

0
votes

Here's how you can do it:

public static class Extensions
{
    public static IEnumerable<T> MyDistinct<T, V>(this IEnumerable<T> query,
                                                    Func<T, V> f, 
                                                    Func<IGrouping<V,T>,T> h=null)
    {
        if (h==null) h=(x => x.First());
        return query.GroupBy(f).Select(h);
    }
}

This method allows you to use it by specifying one parameter like .MyDistinct(d => d.Name), but it also allows you to specify a having condition as a second parameter like so:

var myQuery = (from x in _myObject select x).MyDistinct(d => d.Name,
        x => x.FirstOrDefault(y=>y.Name.Contains("1") || y.Name.Contains("2"))
        );

N.B. This would also allow you to specify other functions like for example .LastOrDefault(...) as well.


If you want to expose just the condition, you can have it even simpler by implementing it as:

public static IEnumerable<T> MyDistinct2<T, V>(this IEnumerable<T> query,
                                                Func<T, V> f,
                                                Func<T,bool> h=null
                                                )
{
    if (h == null) h = (y => true);
    return query.GroupBy(f).Select(x=>x.FirstOrDefault(h));
}

In this case, the query would just look like:

var myQuery2 = (from x in _myObject select x).MyDistinct2(d => d.Name,
                    y => y.Name.Contains("1") || y.Name.Contains("2")
                    );

N.B. Here, the expression is simpler, but note .MyDistinct2 uses .FirstOrDefault(...) implicitly.


Note: The examples above are using the following demo class

class MyObject
{
    public string Name;
    public string Code;
}

private MyObject[] _myObject = {
    new MyObject() { Name = "Test1", Code = "T"},
    new MyObject() { Name = "Test2", Code = "Q"},
    new MyObject() { Name = "Test2", Code = "T"},
    new MyObject() { Name = "Test5", Code = "Q"}
};
0
votes

IEnumerable lambda extension:

public static class ListExtensions
{        
    public static IEnumerable<T> Distinct<T>(this IEnumerable<T> list, Func<T, int> hashCode)
    {
        Dictionary<int, T> hashCodeDic = new Dictionary<int, T>();

        list.ToList().ForEach(t => 
            {   
                var key = hashCode(t);
                if (!hashCodeDic.ContainsKey(key))
                    hashCodeDic.Add(key, t);
            });

        return hashCodeDic.Select(kvp => kvp.Value);
    }
}

Usage:

class Employee
{
    public string Name { get; set; }
    public int EmployeeID { get; set; }
}

//Add 5 employees to List
List<Employee> lst = new List<Employee>();

Employee e = new Employee { Name = "Shantanu", EmployeeID = 123456 };
lst.Add(e);
lst.Add(e);

Employee e1 = new Employee { Name = "Adam Warren", EmployeeID = 823456 };
lst.Add(e1);
//Add a space in the Name
Employee e2 = new Employee { Name = "Adam  Warren", EmployeeID = 823456 };
lst.Add(e2);
//Name is different case
Employee e3 = new Employee { Name = "adam warren", EmployeeID = 823456 };
lst.Add(e3);            

//Distinct (without IEqalityComparer<T>) - Returns 4 employees
var lstDistinct1 = lst.Distinct();

//Lambda Extension - Return 2 employees
var lstDistinct = lst.Distinct(employee => employee.EmployeeID.GetHashCode() ^ employee.Name.ToUpper().Replace(" ", "").GetHashCode()); 
-1
votes

I found this as the easiest solution.

public static IEnumerable<TSource> DistinctBy<TSource, TKey>
        (this IEnumerable<TSource> source, Func<TSource, TKey> keySelector)
    {
        return source.GroupBy(keySelector).Select(x => x.FirstOrDefault());
    }