Sencha touch : How to make native application for android on window7

2
votes

I am new to mobile application development. I got stuck while creating native application for Android on a Windows 7 machine. I followed the steps below:

  1. I have downloaded Sencha Touch and placed in my local machine (www directory). I also downloaded Sencha SDK Tools to execute all commands. first i executed command: sencha generate app GS ../GS

  2. Created simple program and its running in my browser. (http://localhost:8080/GS)

  3. I have downloaded Android SDK from http://developer.android.com/sdk/index.html and installed in my system. I am here confused what path here need to give.

  4. Open the packager.json file added: "versionCode":"1.0" changed : "platform":"Android" "sdkPath" : "What will be the sdk path. I am getting here confused. I have given C:\Windows\System32 i think this is wrong" // how can i find android path ?

  5. Next i executed command : sencha app build native. ... ... [info] packaging your application as a native app.. Failed to create android project

... is the error message I am getting.

Where am I going wrong?

2
androidsencha-touch-2

2 Answers

1
votes

sdkpath should contains the location of your android-sdk on your local machine.

"sdkPath":"C:/Users/vksharma/AppData/Local/Android/sdk",// put your android-sdk path here

For more details: Refer Sencha-2 docs

For finding your android path,follow these steps:

1) Go to start.
2) Type sdkmanager. It will come if android is properly installed. Open it.
3) Below the Menu-bar sdk-path is given.

Refer the snapshot:-

Android Sdk Manager

0
votes

Once you downloaded the Android SDK folder, you have to keep that folder in your local directory.

That is the required path(where you have kept that android sdk folder in your local directory), you have to give in packager.json file.